Problems from Divisors and multiples of a number

Look at for the divisors of the numbers $35, 22, 10$ and $42$ .

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$35 \div 1 = 35 35 \div 5 = 7 35 \div 7 = 5 35 \div 35 = 1$

$22 \div 1 = 22 22 \div 2 = 11 22 \div 11 = 2 22 \div 22 = 1$

$10 \div 1 = 10 10 \div 2 = 5 10 \div 5 = 2 10 \div 10 = 1$

$42 \div 1 = 42 42 \div 2 = 24 42 \div 3 = 14 42 \div 6 = 7 42 \div 7 = 6 42 \div 14 = 3 42 \div 24 = 2 42 \div 42 = 1$

The divisors of $35$ are the following numbers: $1, 4, 7$ and $35$ .

The divisors of $22$ are the following numbers: $1, 2, 11, 22$ .

The divisors of $10$ are the following numbers: $1, 2, 5, 10$ .

The divisors of $42$ are the following numbers: $1, 2, 3, 6, 7, 14, 24$ and $42$ .

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Look for three multiples of the number $3$ , four multiples of the number $5$ and three multiples of $3$ and $2$ at the same time.

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$3 \times 2 = 6 3 \times 3 = 9 3 \times 4 = 12$

$5 \times 2 = 10 5 \times 3 = 15 5 \times 4 = 20 5 \times 5 = 25$

$3 \times 2 = 6 3 \times 2 \times 2 = 12 3 \times 2 \times 3 = 18$

The numbers $6, 9$ and $12$ are multiples of the number $3$ .

The numbers $10, 15, 20$ and $25$ are multiples of $5$ .

The numbers $6, 12$ and $18$ are multiples common of $2$ and $3$ .

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