Problems from Multiplication of fractions

Calculate:

  1. $$\dfrac{5}{9}\cdot\dfrac{-4}{8}$$
  2. $$\dfrac{-3}{7}\cdot\dfrac{-1}{10}$$
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Development:

  1. $$\dfrac{5}{9}\cdot\dfrac{-4}{8}=\dfrac{5}{9}\cdot\dfrac{-1}{2}=\dfrac{5\cdot(-1)}{9\cdot2}=\dfrac{-5}{18}$$
  2. $$\dfrac{-3}{7}\cdot\dfrac{-1}{10}=\dfrac{-3\cdot(-1)}{7\cdot10}=\dfrac{3}{70}$$

Solution:

  1. $$\dfrac{-5}{18}$$
  2. $$\dfrac{3}{70}$$
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