Problems from Representation of complex numbers in the plane

Development:

For the conjugate we must write the vector $(a,-b)$. Therefore as the complex is $13+8i$, we will have: $(13,-8)$ the vector of the conjugate.

Solution:

$(13,-8)$.

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Development:

We must only write the coefficient of the real part and that of the imginary part. This is to identify $a$ and $b$ from a complex number given in its binomic form.

$3+5i\Rightarrow (a,b)=(3,5)$

$\sqrt{7}-9i\Rightarrow (a,b)=(\sqrt{7},-9)$

${\displaystyle \frac{4}{7}}i\Rightarrow (a,b)=(0,{\displaystyle \frac{4}{7}})$

${\displaystyle \frac{\sqrt{4}}{5}}\Rightarrow (a,b)=({\displaystyle \frac{\sqrt{4}}{5}},0)$

Solution:

$(3,5),(\sqrt{7},-9),(0,{\displaystyle \frac{4}{7}}),({\displaystyle \frac{\sqrt{4}}{5}},0)$.

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Development:

For the opposite of a complex number we must write the vector $(-a,-b)$. In our case it is: $(-13,-8)$.

Solution:

$(-13,-8)$.

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