Problems from The factorial of a number

Calculate the value of:

$4!$
$6!$
$(8 - 3)!$
$(2^{3})!$
$2^{3!}$

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Development:

$4! = 4 \cdot 3 \cdot 2 \cdot 1 = 24$
$6! = 6 \cdot 5 \cdot 4 \cdot 3 \cdot 2 \cdot 1 = 720$
$(8 - 3)! = 5! = 5 \cdot 4 \cdot 3 \cdot 2 \cdot 1 = 120$
$(2^{3})! = 8! = 8 \cdot 7 \cdot 6 \cdot 5 \cdot 4 \cdot 3 \cdot 2 \cdot 1 = 40.320$
$2^{3!} = 2^{3 \cdot 2 \cdot 1} = 2^{6} = 64$

Solution:

$4! = 24$
$6! = 720$
$(8 - 3)! = 120$
$(2^{3})! = 40.320$
$2^{3!} = 64$

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