Calculate the value of:
- $$4!$$
- $$6!$$
- $$(8-3)!$$
- $$(2^3)!$$
- $$2^{3!}$$
See development and solution
Development:
-
$$4! = 4\cdot3\cdot2\cdot1 = 24$$
-
$$6! = 6\cdot5\cdot4\cdot3\cdot2\cdot1 = 720$$
-
$$(8-3)! = 5! = 5\cdot4\cdot3\cdot2\cdot1 = 120$$
-
$$(2^3)! = 8! = 8\cdot7\cdot6\cdot5\cdot4\cdot3\cdot2\cdot1 = 40.320$$
- $$2^{3!}= 2^{3\cdot2\cdot1}=2^6=64$$
Solution:
-
$$4! = 24$$
-
$$6! = 720$$
-
$$(8-3)! = 120$$
-
$$(2^3)!= 40.320$$
- $$2^{3!}=64$$