Problems from The probability function

The owner of a casino fakes two dices so that in dice $A$ we can never get a $6$ (and get twice as many ones), and in dice $B$ we never get a $5$ (and twice as many twos).

Fill in the following table of probabilities for every dice:

result dice A	probability
$1$	?
$2$	?
$3$	$1 / 6$
$4$	?
$5$	?
$6$	0

result dice B	probability
$1$	?
$2$	?
$3$	$1 / 6$
$4$	?
$5$	?
$6$	?

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Development:

The impossible events have zero probability $(A = 6, B = 5)$ . As we are been told, there is twice the probability of observing events $A = 1$ and $B = 2$ (probability $2 / 6$ ):

result dice A	probability
$1$	$2 / 6$
$2$	$1 / 6$
$3$	$1 / 6$
$4$	$1 / 6$
$5$	$1 / 6$
$6$	$0$

result dice B	probability
$1$	$1 / 6$
$2$	$2 / 6$
$3$	$1 / 6$
$4$	$1 / 6$
$5$	$0$
$6$	$1 / 6$

Solution:

result dice A	probability
$1$	$2 / 6$
$2$	$1 / 6$
$3$	$1 / 6$
$4$	$1 / 6$
$5$	$1 / 6$
$6$	$0$

result dice B	probability
$1$	$1 / 6$
$2$	$2 / 6$
$3$	$1 / 6$
$4$	$1 / 6$
$5$	$0$
$6$	$1 / 6$

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