Problems from Distance from a point to a plane in space

Given the point $P = (1, 2, 3)$ , find the distance between $P$ and the plane $π$ :

$π : 4 x + 2 y - 4 z + 3 = 0$

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Development:

$d (P, π) = \frac{| A \cdot p_{1} + B \cdot p_{2} + C \cdot p_{3} + D |}{\sqrt{A^{2} + B^{2} + C^{2}}} = \frac{| 4 \cdot 1 + 2 \cdot 2 - 4 \cdot 3 + 3 |}{\sqrt{4^{2} + 2^{2} + (- 4)^{2}}} = \frac{1}{6}$

Solution:

$d (P, π) = \frac{1}{6}$

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