Solve the following exponential equation: $$10^{\frac{3x-1}{2x+1}}=100$$
See development and solution
Development:
$$10^{\frac{3x-1}{2x+1}}=100$$
We reduce to the same basis and obtain $$$10^{\frac{3x-1}{2x+1}}=10^2$$$
Then, equalling exponents, we get $$$\dfrac{3x-1}{2x+1}=2 \Rightarrow 3x-1=4x+2 \Rightarrow x=-3$$$
Solution:
$$x=-3$$