Problems from Absolute, relative, cumulative frequency and statistical tables

In a survey to $20$ inhabitants of Barcelona on how many times a week they buy in small shops in the city, the obtained answers are: $2, 0, 3, 1, 4, 5, 1, 1, 2, 3, 0, 0, 1, 3, 2, 5, 4, 3, 3, 2$

Construct a frequency table and calculate what percentage of the population make purchases $3$ times or less per week in small shops.

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Development:

Purchases in small shops	Absolute frequency $f_{i}$	Relative frequency $n_{i}$	Cumulative frequency $F_{i}$	Cumulative relative frequency $N_{i}$
$0$	$3$	$\frac{3}{20}$	$3$	$\frac{3}{20}$
$1$	$4$	$\frac{4}{20}$	$3 + 4 = 7$	$\frac{7}{20}$
$2$	$4$	$\frac{4}{20}$	$3 + 4 + 4 = 11$	$\frac{11}{20}$
$3$	$5$	$\frac{5}{20}$	$11 + 5 = 16$	$\frac{16}{20} = 0, 8 = 80 %$
$4$	$2$	$\frac{2}{20}$	$16 + 2 = 18$	$\frac{18}{20}$
$5$	$2$	$\frac{2}{20}$	$18 + 2 = 20$	$\frac{20}{20} = 1$
$\sum$	$20$	$1$

Solution:

Purchases in small shops	Absolute frequency $f_{i}$	Realtive frequency $n_{i}$	Cumulative frequency $F_{i}$	Cumulative relative frequency $N_{i}$
$0$	$3$	$\frac{3}{20}$	$3$	$\frac{3}{20}$
$1$	$4$	$\frac{4}{20}$	$3 + 4 = 7$	$\frac{7}{20}$
$2$	$4$	$\frac{4}{20}$	$3 + 4 + 4 = 11$	$\frac{11}{20}$
$3$	$5$	$\frac{5}{20}$	$11 + 5 = 16$	$\frac{16}{20} = 0, 8 = 80 %$
$4$	$2$	$\frac{2}{20}$	$16 + 2 = 18$	$\frac{18}{20}$
$5$	$2$	$\frac{2}{20}$	$18 + 2 = 20$	$\frac{20}{20} = 1$
$\sum$	$20$	$1$

$80 %$ of the survey participants make purchases $3$ times or less per week in small shops.

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