Equivalent fractions: simplification and irreducible fraction

Imagine you have the two fractions 34 and 68 and we apply it to an integer, 32 for instance, and we get the same result:

(32:4)(3)=8(3)=24 (32:(8))6=46=24

In this case, we can say that 34 and 68 are equivalent fractions.

In this example, we can check that if we multiply the numerator of the first fraction by the denominator of the second, the result is the same as if we multiply the denominator of the first fraction by the second numerator: 3(8)=46

In general, we say that two fractions ab and cd, with b0 and c0, are equivalent if: ad=bc

To express it we write down: abcd or ab=cd.

The relation "be equivalent to" has the following properties:

Reflexive property

Every fraction is equivalent to itself, ab=ab because ab=ab.

Symmetric property

If ab is equivalent to cd, then the fraction cd is equivalent to ab.

If ab=cd means that ad=bc, then cb=da that means cd=ab.

Transitive property

If one fraction is equivalent to another, and this last one is equivalent to a third fraction, then the first one is equivalent to the third one:

ab=cdcd=nm} then ab=nm

The equivalence between fractions is an equivalence relation that classifies the fractions into classes of equivalent fractions.

A class of equivalent fractions is a set of fractions where all of them are equivalent, and any other fraction which isn't into the set is not equivalent to any of them.

Every class of equivalence is a rational number.

Obtain equivalent fractions

Consider the fraction ab and an integer m nonzero.

If we multiply the numerator and denominator of the fraction ab by m the result is: ambm

This new fraction is equivalent to ab, ie: ambm=ab due to: (am)b=a(bm)

Example

Consider the fraction 12, graphically

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Is

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If we multiply the numerator and denominator of the fraction by m=3, we obtain: 12=1323=36, that graphically is

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The painted parts are the same, so the fractions are equivalent!

A very important case of equivalent fractions appears when we have negative denominators, because if we want to interpret the fraction as an integer division, having a negative divisor makes it very difficult, so if we multiply numerator and denominator by 1 then we obtain an equivalent fraction with positive denominator, and therefore much easier to operate.

Example

If we want to calculate 57 of 49, we can do (49:(7))5 which is not an easy calculation. However, the fraction 5(1)7(1)=57 is equivalent to the first one, and it is more efficient: (49:7)(5)=7(5)=35

On the other hand, the fraction 5(7)7(7)=3549 is also equivalent to the last one, and the calculation is much easier: (49:49)(35)=1(35)=35

Consider now the fraction 1020 and 24. They are equivalent: 104=20(2) We can say that we have obtained the first one from the second one multiplying numerator and denominator by m=5, or we can say that we have done it dividing by m=5 the numerator and denominator of the first fraction. In this last case, we say we have simplified the fraction 1020 a 24.

To simplify a fraction means to divide numerator and denominator by the same integer.

Example

The fraction 412 can be simplified dividing numerator and denominator by 2.

4:212:2=26 The obtained fraction is equivalent to the first one: 46=122 And, ¿it is possible to simplify it again? The answer is yes, for example, we can divide numerator and denominator by two:

2:26:2=13

And now, ¿is it possible to simplify it again? And the answer is no, because there is no integer that divides 1 and 3 at the same time.

Those fractions that can not be simplified are called irreducible.

Formally, we say that a fraction ab is irreducible if the numerator and denominator are coprime, ie, m.c.d(a,b)=1.

Example

If we have these fractions 34 and 25, they can not be simplified because 2, 3 and 5 are prime numbers.

Thus, to find an equivalent fraction to another one that would be irreducible, we must simplify using the greatest common divisor.

Example

Suppose we have this fraction 412. To simplify it we must do:

  1. Calculate the greatest common divisor of numerator and denominator. In our example, 4=22 and 12=223, so g.c.d(4,12)=22=4
  2. Divide numerator and denominator by their gcd:4:412:4=13

This new fraction is equivalent: 43=121

Graphically

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And it is irreducible: g.c.d(1,3)=1.

Two irreducible and different fractions will never be equivalent, and for this reason every one will be in a different representation class.

Thus, if we want to make a reference for a class we must use the irreducible fraction, and we will call it the class representative.