General term of an arithmetical progression

To find the general term of an arithmetical progression we consider the formula that defines these progressions: an+1an=d.

This equality expresses that, in the arithmetical progressions, every term is obtained by adding the difference to the previous term. This way, we can define the progression in a recursive way and then: an+1=an+d

If we apply this law recursively to construct the succession, we obtain: a2=a1+d a3=a2+d=(a1+d)+d=a1+2d a4=a3+d=(a1+2d)+d=a1+3d a5=a4+d=(a1+3d)+d=a1+4d

And, in general, we have an=a1+(n1)d This expression relates any term of the succession to the first using the difference of the progression.

Example

We want to find the number that is in position 37 of the succession (8,11,14,17,20,) We notice that it is an arithmetical progression because the difference between all the terms is constant and equal to 3.

As the first term is a1=8, and the difference is d=3, we have: an=8+(n1)3 Since we want to find the term a37, we can proceed: a37=8+(371)3=8+336=8+108=116