Problems from Constant function, Linear function and Affine function

Development:

Let's start with the first one:

1) $y=-2x+1$

We observe that the expression is of the type $y=mx+n$, with

$m=-2$

$n=1$

Therefore it is an affine function with slope $-2$.

2) $y=-1$

In this case the function corresponds to one of the type $f(x)=k$, where $k$ is constant.

Therefore, this is a constant function with slope $0$.

3) $y=x$

Finally, we have a function of the type $f(x)=mx$ with $m=1$.

Therefore this is a linear function with slope $m=1$.

Solution:

1) $y=-2x+1$

Affine function.

Slope $m=-2$.

2) $y=-1$

Constant function.

Slope $m=0$.

3) $y=x$

Linear function.

Slope $m=1$.

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