Property of Darboux (theorem of the intermediate value)

Let f(x) be a continuous function defined in the interval [a,b] and let k be a number between the values f(a) and f(b) (such that f(a)kf(b)).

Then some value c exists in the interval [a,b] such that f(c)=k.

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This property is very similar to the Bolzano theorem. In fact it is possible to deduce it very easily:

Taking the function g(x)=f(x)k it is easy to see that it will satisfy the Bolzano theorem:

As f(a)kf(b)f(a)k0f(b)kg(a)0g(b)

g(a)g(b)0, then by Bolzano a value c exists in the interval [a,b] such that g(c)=0.

But of course 0=g(c)=f(c)kf(c)=k and the property of Darboux is proven.

Let's see some examples of application:

Example

We are going to look for the existence of a solution to the equation (x1)3=2.

We define the function f(x)=(x1)3.

We have to look for an interval such that the value 2 falls inside .

Let's take, for example, the interval [1,3].

The image of the interval is f([1,3])=[f(1),f(3)]=[0,8] and clearly the value 2 belongs to it.

Therefore, we can be assured of the existence of at least one solution to the equation (x1)3=2 in interval [0,8].

Example

We will look to see if solutions for the equation 3=ex+2x exist.

We define the function f(x)=ex+2x.

We have to look for an interval such that its image contains the value 3.

For example, we are going to evaluate the function in: f(0)=1f(1)=e+2>3

Moreover, the exponential function is increasing, as is the function f(x)=2x, so our function is increasing and consistently the image of [0,1] contains the value 3.

Therefore, using the property, we can be sure that at least one solution to our equation exists inside the interval [0,1].